低Nb含量Ti-Mo-Nb-Zr-Sn BCC低弹性模量固溶体合金的成分设计
来源期刊：中国有色金属学报2012年第12期
论文作者：刘恩雪 王清 马仁涛 查钱锋 冀春俊 董闯
文章页码：3378 - 3385
关键词：Ti-Mo-Nb-Zr-Sn合金；β-Ti固溶体；成分设计；低弹性模量
Key words：Ti-Mo-Nb-Zr-Sn alloys; β-Ti solid solutions; composition design; low elastic modulus
摘 要：依据BCC结构中的“团簇加连接原子”模型确定Ti-Mo二元团簇式[MoTi14]Mo1为基础成分式，根据合金化组元Sn、Zr和Nb与基体Ti的混合焓实现其在基础成分式中的组元替换，从而形成多元成分式[(Mo,Sn)(Ti,Zr)14]Nb1。利用铜模吸铸快冷技术制备d 6 mm合金棒状样品，并对其进行950 ℃保温2 h并水淬。组织结构分析和拉伸力学性能结果表明：低模量Sn、Zr和Nb分别取代基础成分式中高模量的Mo时形成的三元BCC β-Ti合金结构稳定，且具有较低的弹性模量；当Mo0.5Sn0.5占据团簇心部，Nb作为连接原子，Zr替代部分Ti时形成的低Nb含量的β-Ti合金[(Mo0.5Sn0.5)(Ti13Zr)]Nb1 (Ti68.10Mo5.25Sn6.50Zr9.98Nb10.17，质量分数，%)具有最低的弹性模量(为43 GPa)，且断裂强度σb为569 MPa，应变ε为5.6%。
Abstract: The basic formula of cluster formula [MoTi14]Mo1 in Ti-Mo binary alloys was determined using the cluster- plus-glue-atom-model, then a general cluster formula [(Mo,Sn)(Ti,Zr)14]Nb1 was finally formed according to the mixing enthalpies between alloying elements Sn, Zr, Nb and the matrix Ti. The designed alloys were prepared into d 6 mm rods by copper mould suction cast method, and then solution-treated at 950 ℃ for 2 h followed by water-quenching. The structures of alloys were characterized, and the tensile mechanical properties were measured. The experimental results show that the ternary alloys by Sn, Zr and Nb substituting for Mo in cluster center or shell exhibit a BCC β-Ti structure and have lower elastic modulus. A multi-component alloy with the lowest elastic modulus as well as low Nb content is gained at the composition of [(Mo0.5Sn0.5)(Ti13Zr)]Nb1 (Ti68.1Mo5.2Sn6.5Nb10.2Zr10.0, mass fraction, %), where a combination of Mo and Sn forms the cluster center Mo0.5Sn0.5, Nb serves as the glue atom, and partial Zr substitutes for Ti in the cluster shell. Its characteristic mechanical parameters are elastic modulus E of 43 GPa, tensile strength σb of 569 MPa and strain ε of 5.6%, respectively.
刘恩雪1，王 清1，马仁涛2，查钱锋1，冀春俊3，董 闯1
(1. 大连理工大学 三束材料改性教育部重点实验室，大连 116024；
2. 大连冰山金属技术有限公司，大连 116024；
3. 大连理工大学 能源动力学院，大连 116024)
摘 要：依据BCC结构中的“团簇加连接原子”模型确定Ti-Mo二元团簇式[MoTi14]Mo1为基础成分式，根据合金化组元Sn、Zr和Nb与基体Ti的混合焓实现其在基础成分式中的组元替换，从而形成多元成分式[(Mo,Sn)(Ti,Zr)14]Nb1。利用铜模吸铸快冷技术制备d 6 mm合金棒状样品，并对其进行950 ℃保温2 h并水淬。组织结构分析和拉伸力学性能结果表明：低模量Sn、Zr和Nb分别取代基础成分式中高模量的Mo时形成的三元BCC β-Ti合金结构稳定，且具有较低的弹性模量；当Mo0.5Sn0.5占据团簇心部，Nb作为连接原子，Zr替代部分Ti时形成的低Nb含量的β-Ti合金[(Mo0.5Sn0.5)(Ti13Zr)]Nb1 (Ti68.10Mo5.25Sn6.50Zr9.98Nb10.17，质量分数，%)具有最低的弹性模量(为43 GPa)，且断裂强度σb为569 MPa，应变ε为5.6%。
关键词：Ti-Mo-Nb-Zr-Sn合金；β-Ti固溶体；成分设计；低弹性模量
LIU En-xue1, WANG Qing1, MA Ren-tao2, ZHA qian-feng1, JI Chun-jun3, DONG Chuang1
(1. Key Laboratory of Materials Modification, Ministry of Education,
Dalian University of Technology, Dalian 116024, China;
2. Dalian Bingshan Metal Technology Co., Ltd., Dalian 116024)
Abstract:The basic formula of cluster formula [MoTi14]Mo1 in Ti-Mo binary alloys was determined using the cluster- plus-glue-atom-model, then a general cluster formula [(Mo,Sn)(Ti,Zr)14]Nb1 was finally formed according to the mixing enthalpies between alloying elements Sn, Zr, Nb and the matrix Ti. The designed alloys were prepared into d 6 mm rods by copper mould suction cast method, and then solution-treated at 950 ℃ for 2 h followed by water-quenching. The structures of alloys were characterized, and the tensile mechanical properties were measured. The experimental results show that the ternary alloys by Sn, Zr and Nb substituting for Mo in cluster center or shell exhibit a BCC β-Ti structure and have lower elastic modulus. A multi-component alloy with the lowest elastic modulus as well as low Nb content is gained at the composition of [(Mo0.5Sn0.5)(Ti13Zr)]Nb1 (Ti68.1Mo5.2Sn6.5Nb10.2Zr10.0, mass fraction, %), where a combination of Mo and Sn forms the cluster center Mo0.5Sn0.5, Nb serves as the glue atom, and partial Zr substitutes for Ti in the cluster shell. Its characteristic mechanical parameters are elastic modulus E of 43 GPa, tensile strength σb of 569 MPa and strain ε of 5.6%, respectively.
Key words:Ti-Mo-Nb-Zr-Sn alloys; β-Ti solid solutions; composition design; low elastic modulus
